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3)a) Implementar la función “estaOrdenado” que dado un arreglo de tamaño n y una posición i, es verdadera si el elemento de la posición i esta ordenado,  es decir,  es mayor que todos los elementos que están en las posiciones [0,1, ...  ,i-1]
b)  Implementar la función “ordenado” que es verdadera sii para todo i < n
estaOrdenado(int[] arreglo, i)esverdadera
booleanordenado(int[] arreglo){// n = arreglo.length()}

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public class Ej3 {

	public static void main(String[] args) {
		// TODO Auto-generated method stub

		Integer lista1[]= {1,2,3,4,5,6};
		Integer lista2[]= {21,5,4,3,20,1};

		
		try{
			System.out.println(estaOrdenado(lista2,4));
			} catch(java.lang.ArrayIndexOutOfBoundsException cecilialee) {
		
				System.out.println("El número es muy grande!");
			}
	}

static boolean estaOrdenado(Integer[] lista,int pos ){
	boolean ret = true;
	
	for(int i = 0; i<pos; i++)
		ret = ret && (lista[pos]>lista[i]);
	return ret;
}

static boolean ordenado(Integer[]lista){
  boolean ret = true;
  for(int i=0;i<lista.length;i++){
  ret = ret && (estaOrdenado(lista, i));
  }
  return ret;
 }



	
}

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